getting Count of a digits present in a numeric value

RE: getting Count of a digits present in a numeric value

Dan Lluhi — Wed, 13 Jun 2018 14:02:19 GMT

Hi, if you want to get everything to the right of the semicolon, you can use the function fn!split(ri!text,";"), which will create an array of text strings. From there you can get the second element, which would be your 0222001.

If instead you want the length of the whole string, but just without the semicolon, you can use the function fn!stripwith(ri!text,";"), which will return a single text string without any semi colons at all.

Here's the documentation for each of the functions:
docs.appian.com/.../fnc_text_split.html
docs.appian.com/.../fnc_text_stripwith.html

Thanks,
Dan

RE: getting Count of a digits present in a numeric value

dippomanm607 — Wed, 13 Jun 2018 13:57:20 GMT

IF I have an expression like this : "MKS180;0222001" and need to remove the semicolon in between which function I should use?

RE: getting Count of a digits present in a numeric value

Dan Lluhi — Wed, 13 Jun 2018 13:49:55 GMT

Hi, the function fn!len() will return the number of characters in an input string. If you pass it a number, it'll convert the number to a string and perform the same action. Here is the documentation for it: docs.appian.com/.../fnc_text_len.html

Thanks,
Dan