Time related issue

RE: Time related issue

danb0002 — Fri, 20 Dec 2019 08:02:05 GMT

Thanks Peter , I got my solution

RE: Time related issue

Peter Lewis — Thu, 19 Dec 2019 19:27:39 GMT

Agreed with Mike - troubleshooting is much easier one at a time. Also, since you're looking for just the days, I'd suggest putting floor() around your interval result, which should give you the number of days in an integer.

RE: Time related issue

Mike Schmitt — Thu, 19 Dec 2019 17:29:22 GMT

I suggest you write an expression rule called something like "APP_getElapsedDaysBetweenDates" that accepts two DATETIME parameters and returns a result that matches what you are after - i.e. whole numbers (0, 1, etc) for business days, or decimals to represent days and partial days, and also handles null-checking on either or both of the inputs. After that, you can simply call that rule and pass in the two columns from your report within the logic of your a!forEach statement. Doing it this way will make it much more easy to initially test that the math you're trying to do is both working without error, and returning the exact return value you're expecting.

RE: Time related issue

danb0002 — Thu, 19 Dec 2019 17:23:53 GMT

Hi Peter i understand that but I'm getting the result

0::00:00:11.207

which i don't need that i need this result only in days . because some task assigned in same date and completed in same date so for that scenario it should be 0 .... i hope you are getting my point

RE: Time related issue

Mike Schmitt — Thu, 19 Dec 2019 17:23:20 GMT

You would be able to handle this case in the logic of your a!forEach() expression once you get the math working for non-null cases. Just wrap the expression in an if() statement where you check i.e. "isnull(fv!item.c3)" and return a different value in that case.

RE: Time related issue

danb0002 — Thu, 19 Dec 2019 17:18:07 GMT

in some case start date is null

RE: Time related issue

Mike Schmitt — Thu, 19 Dec 2019 17:03:34 GMT

FYI, danb0002 - you can also do a lot of this troubleshooting yourself in a blank Expression Rule editor window, testing out what operators work with which date/datetime values, etc. That's what a lot of us do ourselves when providing support.

For ex.

with(
  local!today: datetime(2019, 12, 19, 15, 47),
  local!pastDate: datetime(2019, 12, 14, 07, 33),
  
  todecimal(local!today - local!pastDate)
)

RE: Time related issue

Peter Lewis — Thu, 19 Dec 2019 16:58:31 GMT

Actually I think you might need it like this then:

a!gridTextColumn(
  label: "Duration",
  data: a!forEach(
    items: local!dataset.data,
    expression: todecimal(todatetime(fv!item.c11) - todatetime(fv!item.c3))
  )
)

RE: Time related issue

danb0002 — Thu, 19 Dec 2019 16:51:35 GMT

Hi Please understand my situation i have two date Start Date and End Date

for start date data:index(local!dataset.data,"c3",{}) and End date data:index(local!dataset.data,"c11",{}) in grid

i need to subtract these two date ( end date - start date ) to get the duration in days

EX- Jan 6, 2019 11:34 AM start date and end date is Feb 5, 2019 11:34 AM

RE: Time related issue

Mike Schmitt — Thu, 19 Dec 2019 14:49:59 GMT

I'm not sure what all you might have so far, but to resolve that error perhaps try this instead:

expression: todecimal(fv!item.c11) - todecimal(fv!item.c3)

RE: Time related issue

danb0002 — Thu, 19 Dec 2019 14:42:18 GMT

getting this error

Expression evaluation error at function 'todecimal' parameter 1 [line 92]: Cannot sub incompatible operands of type Any Type and type Any Type.

RE: Time related issue

Peter Lewis — Thu, 19 Dec 2019 14:13:36 GMT

If you need to do this in a grid, just reference both of your columns using a!forEach(). Here's an example of how you can set up the column:

a!gridTextColumn(
  label: "Duration",
  data: a!forEach(
    items: local!dataset.data,
    expression: todecimal(fv!item.c11 - fv!item.c3)
  )
)

I used the decimal because it will give you a count in days - if you want to format it differently, you might have to parse out the parts of the interval (see davidl's post above mine).

RE: Time related issue

davel001150 — Thu, 19 Dec 2019 13:35:56 GMT

I tried this:

datetime(2011, 12, 13, 12, 0, 0) - datetime(2011, 12, 10, 10, 0, 0)

in one of the example boxes, and this was the result:

Type	Interval (Day to Second)
Value	3::02:00:00.000

It's Interval format, 3 days and 2 hours. So the - (minus) operator should take care of it.

Let us know if you have further problems.

RE: Time related issue

danb0002 — Thu, 19 Dec 2019 08:47:00 GMT

i want subtract start date and end date ... to get time in duration .... is it possible

Jun 9, 2019 11:34 AM start date

Aug 6, 2019 11:34 AM end date

RE: Time related issue

Mike Schmitt — Wed, 18 Dec 2019 18:53:30 GMT

What have you tried so far / what exactly is the problem you're having?