populating the date field values in a grid

RE: populating the date field values in a grid

sravanis — Wed, 16 Aug 2017 11:46:18 GMT

Hi,

Thanks for your suggestions, I will try in above format.

RE: populating the date field values in a grid

Vinay Kumar Rai — Wed, 16 Aug 2017 10:47:22 GMT

Hi Sravansi,
Agree with Jocob, you can create the additional CDT with all the filed on the GRID and use of apply function to populate the data on the CDT variable,
Example :
local!AllDetails:
apply(

rule!CreateDataFormat(
Index:_
MainData:local!MainData
),
1 + enumerate (count(local!MainData))

and On the Expression : CreateDataFormat
type!MyNewCDT(
Id : ri!MainData[ri!Index].Id,
date1: ri!MainData[ri!Index].date,
date2: index(ri!MainData,ri!Index+1,null)
)

hope it helpful

RE: populating the date field values in a grid

Shivam Gupta — Wed, 16 Aug 2017 05:43:18 GMT

Hi Sravanis,
Can you brief me more about the scenario, like what you meant by "original date"? and how date2 column is changing upon selecting date1 field ?
Also if you just want to show the date2 of row 1 in date1 of row 2 while you add a row. Just create a local variable and save the date2 value of row1 as it changes and have the same value in row2 date1 field when you create a new row..

RE: populating the date field values in a grid

sravanis — Wed, 16 Aug 2017 04:27:07 GMT

Hi,

Actually the data in database should not change, I need to show that format only in grid.

RE: populating the date field values in a grid

Jacob Grafenstein — Mon, 14 Aug 2017 14:53:06 GMT

There are many implementation strategies you could use to achieve this desired result. What do your CDTs look like? One way of achieving this would be to create a field in your CDT that acts as a pointer back the previous CDT. For the first CDT in the list, the pointer would be null. For every subsequent CDT in the list, the pointer would point back to the previous CDT. Then, you can access the previous CDT's date2 field.