Finding repeated items in an array

RE: Finding repeated items in an array

saivineeths — Wed, 21 Nov 2018 06:16:57 GMT

Hi Harsha,

Please find the code snippet.

load(
local!a:{1,2,3,3,45,45},
local!b:a!forEach(
items:local!a,
expression:
if(count(
wherecontains(fv!item,local!a))>1,fv!item,{})
),
union(local!b,local!b)
)

Regards,
sai Vineeth

RE: Finding repeated items in an array

Abhay Giri — Wed, 21 Nov 2018 05:41:47 GMT

Hi,

try below one:

load(
local!data: {
1,
2,
3,
4,
1,
2,
5,
4
},
local!dupplicateData: a!forEach(
items: local!data,
expression: if(
length(
wherecontains(
fv!item,
local!data
)
) >= 2,
fv!item,
{}
)
),
union(
local!dupplicateData,
local!dupplicateData
)
)

regards
abhay

RE: Finding repeated items in an array

Hema — Wed, 21 Nov 2018 03:11:14 GMT

Hi Harsha,

The below code snippet would be helpful to you,

load(
  local!data: {1,2,3,4,3,5,6,5,4,7},
  local!uniqueData: union(
    local!data,
    local!data
  ),
  reject(
    fn!isnull,
    a!forEach(
      items: local!uniqueData,
      expression: if(
        count(
          wherecontains(
            fv!item,
            local!data
          )
        ) > 1,
        fv!item,
        null
      )
    )
  )
)

Hope this helps!

Thanks,

Hema

RE: Finding repeated items in an array

aloks0189 — Wed, 21 Nov 2018 00:00:58 GMT

Hi Harsha,

Please find the code snippet demonstrating one of the approach to achieve your requirement below:

load(
  local!items_int: {1, 2, 3, 3, 4, 5, 4, 6},
  local!res,
  local!content: a!forEach(
    local!items_int,
    if(
      count(wherecontains(fv!item, local!items_int)) > 1,
      append(local!res, fv!item),
      append(local!res, {})
    )
  ),
  union(
    local!content,
    local!content
  )
)

/* OUTPUT:  3, 4  (Type: List of Number (Integer) ) */

Hope this will help you.