subtract

RE: subtract

Mike Schmitt — Wed, 19 Jun 2019 16:40:41 GMT

No prob - glad to help ;-)

RE: subtract

mteresa — Wed, 19 Jun 2019 16:36:17 GMT

Use enumerate give me one idea, and its works:

In the end of the rule, i applied this and works. Thank you so much Mike

RE: subtract

Mike Schmitt — Wed, 19 Jun 2019 16:34:23 GMT

What is the value you're passing in for ri!register? Your code as written should be doing one loop for each item in that. So if you only pass in 1, it will only do the forEach loop once.

RE: subtract

mteresa — Wed, 19 Jun 2019 16:32:48 GMT

Thank you, but doesnt work,just give me One register, i think because just do the loop one time

RE: subtract

Mike Schmitt — Wed, 19 Jun 2019 16:22:57 GMT

If I assume correctly that local!contador will be the number of entries you want to return, this is still pretty easy to do:

index(
  local!results,
  enumerate(local!contador)+1, /* if contador=3, this will return array like {1,2,3} */
  null()
)

RE: subtract

mteresa — Wed, 19 Jun 2019 16:20:46 GMT

Hello, thank you for answer.

I tried index but doesnt work for me, becuase the number of registers I need change, can be 1, 2, 3... not is always 1.

RE: subtract

Mike Schmitt — Wed, 19 Jun 2019 16:11:00 GMT

You can't decrement external values from within a loop of a!forEach.

If I understand correctly what you're trying to do, I would just store the results of your a!forEach loop in a local variable (for example) and then get the first index (to get the result in the first position of the array), e.g. "local!results[1]", or "index(local!results, 1, {})".