RE: check an array has mix of values

Stefan Helzle — Fri, 11 Dec 2020 07:34:17 GMT

You can compare a list of values to a single value and it will return a list of booleans for each.

and({10,10,10,10} = 10) => true

and({10,10,10,11} = 10) => false

or({10,10,10,11} = 10) => true

or({23,50,60} = 10) => false

Using an and() would check for all values equal 10. Using an or() would check for at least one value equals 10. That should get your three cases covered.

RE: check an array has mix of values

Dude — Fri, 11 Dec 2020 07:03:41 GMT

Sidharth, please test the code with different lists like local!array1,local!array2,local!mixedArray.wherecontains(10, local!array1),

Replace the list name in the

a!localVariables(
/* Values for testing*/
local!array1: { 10, 10, 10 },
local!array2: { 23, 50, 60 },
local!mixedArray: { 10, 23, 45 },
/*Checking results */
local!howManyOccurrances: wherecontains(10, local!array1),
local!isArrayHasAll10s: length(local!array1) = length(local!howManyOccurrances),
if(
/*If list contains same number, return 1*/
local!isArrayHasAll10s,
1,
/*If list contains different numbers along with given number , return 2*/
if(
local!howManyOccurrances > 0,
2,
/*If list contains different numbers than the given number , return 0*/
0
)
)
)

Note: When you use the logic in the implementation take care of the null checks