functions expression rules

RE: functions expression rules

Harshit Bumb (Appyzie) — Wed, 19 Jan 2022 10:49:31 GMT

Hi there,

This can be another approach. You generate a list of incremental random values, all unique. And then use that array to index from the list of available questions.

Below is the code for the same.

a!localVariables(
  local!questionsData,
  local!array: 1 + tointeger(rand(5) * (1000 - 1)),
  local!sortedArray: rule!BAM_utils_sortArray(
    arrayValues_any: local!array,
    ascending_bool: true
  ),
  local!randomIndex: a!flatten(
    a!forEach(
      items: local!sortedArray,
      expression: wherecontains(fv!item, local!array)
    )
  ),
  index(
    local!questionsData,
    local!randomIndex,
    {}
  )
)

In local!array, I am trying to generate the values in a specific range. The parameter of rand() function will give us 5 values. You can change it to n.

RE: functions expression rules

Stefan Helzle — Wed, 19 Jan 2022 10:12:59 GMT

It does what the name implies. It removes a random item from a given list.

RE: functions expression rules

Stewart Burchell — Wed, 19 Jan 2022 09:31:16 GMT

I tried out a nested loop, where the inner loop generates 5 random integers, and the out loop calls that 10k times. I then flattened the list of arrays and performed a union() on them, The underlying generated list is large enough to reduce the risk of ending up with a list of 4 or less unique integers, but very, very unlikely:

a!localVariables(
  /* local!questions here is the array of quiestions that you'd fetch from the DB*/
  local!questions: a!forEach(
    items: fn!enumerate(10) + 1,
    expression: "Q" & fv!item
  ),
  /* this is where the actual code starts*/
  local!randomNumbers: fn!union(
    tointeger(
      a!flatten(
        a!forEach(
          items: fn!enumerate(10000),
          expression: a!forEach(
            items: fn!enumerate(5) + 1,
            expression: fn!ceiling(fn!rand() * 10, 1)
          )
        )
      )
    ),
    tointeger({})
  )[{ 1, 2, 3, 4, 5 }],
  local!questions[local!randomNumbers]
)

RE: functions expression rules

udhayakumarm000856 — Wed, 19 Jan 2022 09:29:45 GMT

what is the purpose for the rule u used in that line no 4

RE: functions expression rules

Stefan Helzle — Wed, 19 Jan 2022 09:26:39 GMT

Works for me. Can you explain the issue?

RE: functions expression rules

udhayakumarm000856 — Wed, 19 Jan 2022 09:23:23 GMT

This code is not working

RE: functions expression rules

udhayakumarm000856 — Wed, 19 Jan 2022 09:19:14 GMT

it should come randomly means if there are 10 questions I want only 5 questions that is like not comes in ordering it should be like {10,1,5,3,8}

RE: functions expression rules

Stefan Helzle — Wed, 19 Jan 2022 09:14:57 GMT

This may create the same value multiple times. That was my first idea as well and I had no good idea to remove duplicates. I know that union does that, but then I would have to create more than 5 random numbers. But how much? With enough bad luck, all numbers are the same ...

RE: functions expression rules

Stewart Burchell — Wed, 19 Jan 2022 09:05:24 GMT

An alternative would be to fetch all of the questions form the DB (agnostic of their database ids), and then generate a random list of 5 integers in the range of the size of the fetched array (ensuring no duplicate random integers are generated) and then use those to index your fetched array.

RE: functions expression rules

Stefan Helzle — Wed, 19 Jan 2022 07:59:21 GMT

My quick solution is to fetch all the IDs from DB, then randomly remove items until only 5 are left.

a!localVariables(
  local!dbIds: {3,7,42,6,9,13,123,45,889,657},
  reduce(
    rule!TST_RemoveRandomItemFromList(_,_),
    local!dbIds,
    enumerate(5)
  )
)

TST_RemoveRandomItemFromList(
  list(Integer Array),
  dummy(Integer)
  
  remove(
    ri!list,
    ceiling(rand() * count(ri!list))
  )

RE: functions expression rules

Harshit Bumb (Appyzie) — Wed, 19 Jan 2022 06:46:07 GMT

Hi there,

I do not understand this part.

[quote userid="74089" url="~/discussions/f/general/23462/functions-expression-rules"]should be come randomly[/quote]

But what I think is that, when you search for 5, you should get a question with id as 5.
For that, you use queryFilter() in query(). Documentation - https://docs.appian.com/suite/help/21.4/fnc_system_a_queryfilter.html

If you want to combine it with any other filter, then try using logical expressions in query() function where you can pass multiple filters that can be applied all at the same time, or any of them.

I hope it helps.

Thanks,
Harshit