Selectable rows in tree grid

RE: Selectable rows in tree grid

franciscoalfonson0001 — Thu, 16 Jun 2022 16:16:51 GMT

Hello,

to get the subrows to appear, I also used the values of the previous keys so, for example, to get the values for the 5th level, the logic included the values of the 4 previous ones.

I intended to use the Id system I wrote before because if I could get to the Ids of the rows, I'd just search all the Ids that started with the Id of the row I selected.

I also thought about using the element itself as an id, but I wouldn't be able to use the same logic that I applied to get the subrows (as it used the values of the previous values as well)

RE: Selectable rows in tree grid

Stefan Helzle — Thu, 16 Jun 2022 15:59:30 GMT

So, when you expand a top level item, you implemented some logic to find the child items. I suggest to use a similar logic for adding the IDs to the selected items for selection.

RE: Selectable rows in tree grid

franciscoalfonson0001 — Thu, 16 Jun 2022 15:40:55 GMT

Hello,

I've assigned an unique id to every row in the grid ("(Value in first key)-(Value in second key)-..."). I've also made a "Begin with" rule to find all elements in an array that start with a particular string. Is there any way to get all the ids of the grid rows? Or is there another way to approach the situation to make the "hierarchical selection" possible?

RE: Selectable rows in tree grid

Stefan Helzle — Thu, 16 Jun 2022 12:52:44 GMT

I assume that you use the OOTB selection feature of the grid. Each row has a unique ID, adding this ID to the selectionValue parameter of the grid will make these rows selected.

Now, with some logic in the selectionSaveInto, you should be able to add all sub-rows on selection of a parent row.

RE: Selectable rows in tree grid

franciscoalfonson0001 — Thu, 16 Jun 2022 11:07:49 GMT

rows: {
      a!gridRowLayout(
        contents: {
          a!richTextDisplayField(
            value:a!richTextItem("FundHouse Name","STRONG")),
          a!richTextDisplayField(value: ""),
          a!richTextDisplayField(value: "")
        }
      ),
      a!forEach(
        rule!PM_FilterTreeGridAPI(local!revenues, "sFundHouseName"),
        {
          a!localVariables(
            local!show2: false,
            local!value: fv!item,
            {
              a!gridRowLayout(
                contents: {
                  a!richTextDisplayField(
                    value: a!richTextItem(
                      text: if(
                        local!show2,
                        concat(char(9), "- ", fv!item),
                        concat(char(9), "+ ", fv!item)
                      ),
                      style:if(local!show2,
                      "STRONG","PLAIN"),
                      link: a!dynamicLink(
                        saveInto: a!save(local!show2, not(local!show2))
                      )
                    )
                  ),
                  a!richTextDisplayField(value: ""),
                  a!richTextDisplayField(value: "")
                }
              ),
              a!gridRowLayout(
                showWhen: local!show2,
                contents:{a!richTextDisplayField(value:a!richTextItem(concat(char(9),"Distributor Name"),"STRONG")),
                a!richTextDisplayField(value:""),
                a!richTextDisplayField(value:"")}
              ),
              a!forEach(
                rule!PM_FilterTreeGridAPI(
                  rule!PM_FilterTreeGridfran(local!revenues, { local!value }),
                  "sDistributorName"
                ),
                {a!localVariables(
                
                ...

My code looks like that (I stopped in local variables since there I repeat the process until I finish with the 6th key). To that I would need to add that "hierarchical select" I'm looking for. How would your structure be added to that?

RE: Selectable rows in tree grid

Stefan Helzle — Thu, 16 Jun 2022 10:33:42 GMT

It should be enough to add a saveInto() to add the IDs of the subrows to the selected items. Do you have any code snippets?