Reusing Local Variable

RE: Reusing Local Variable

Tarun — Fri, 13 Jan 2023 07:39:10 GMT

Yes local!value is being reused in your example. And hence you got a list of 3 items towards the end of it. If it were not reused, you would've got just 1 item in result --> 3.

And in your output you mentioned -->

[quote userid="57059" url="~/discussions/f/general/27143/reusing-local-variable"]

1st Iteration

2nd Iteration

3rd Iteration

[/quote]

Either you have misinterpreted the output or I understood your output in a different context. Its not iteration. Its just an item that's appended to the list. So in memory -->

After 1st Iteration --> Local!value = {1}

After 2nd Iteration --> Local!value = {1,2}

After 3rd Iteration --> Local!value = {1,2,3}

Once the loop is finished, {1,2,3} is returned. You can see now that local!value is reused.

RE: Reusing Local Variable

aryan — Fri, 13 Jan 2023 06:24:30 GMT

Can you please specify the use case for doing so

RE: Reusing Local Variable

Mike Schmitt — Wed, 11 Jan 2023 15:28:50 GMT

I think you have a fundamental misunderstanding of what local variables are and what they do (and what they don't do). And what happens when functions act upon them.

A slightly simpler example: If you have a local variable of "local!asdf: {1, 2, 3}" for instance - and you call append() on it: the result of append() is simply an output of the resulting value, it does not (nor would it ever) modify the original local variable it was acting upon.

RE: Reusing Local Variable

Gopu Hema — Wed, 11 Jan 2023 11:02:27 GMT

Thanks!! But its not the exact code or the way that i need, I just want to reuse the variable in next iteration which is updated. But Thanks for the Info

RE: Reusing Local Variable

Gopu Hema — Wed, 11 Jan 2023 11:02:02 GMT

Thanks!! But its not the exact code or the way that i need, I just want to reuse the variable in next iteration which is updated. But Thanks for the Info

RE: Reusing Local Variable

Harshitha Mangamuri — Wed, 11 Jan 2023 09:11:06 GMT

Hi Hema, I hope this will help you in solving your issue.

a!localVariables(
  local!iterations: {1,2,3},
  local!res: a!forEach(
    items: local!iterations,
    expression: {
      a!forEach(
        items: enumerate(fv!index)+1,
        expression: local!iterations[fv!item]
      )
    }
  ),
  local!res
)

RE: Reusing Local Variable

Alex Boerescu — Wed, 11 Jan 2023 08:57:42 GMT

That is the correct behaviour - you cannot modify the value of variables outside of a foreach. You could nest two foreach to achieve this - see the code below.

a!localvariables(
  local!iterations: { 1, 2, 3 },
  a!forEach(
    items: local!iterations,
    expression: a!localVariables(
      local!index: fv!index,
      a!forEach(
        items: enumerate(local!index),
        expression: local!iterations[fv!index]
      )
    )
  )
)

RE: Reusing Local Variable

Harshit Bumb (Appyzie) — Wed, 11 Jan 2023 08:44:02 GMT

You CANNOT update the value of a variable in an expression rule. To update a variable value, you need a user interaction to happen and that is why it is only possible in an interface or a PM.

To achieve your use case, you can make this small tweak in your code and it should work.

a!localVariables(
  local!iterations: { 1, 2, 3 },
  local!value,
  a!forEach(
    items: local!iterations,
    expression: enumerate(fv!index)+1
  )
)