How to convert dictionary to CDT?

RE: How to convert dictionary to CDT?

Brinda — Mon, 08 Jan 2018 05:05:49 GMT

Thank you Malcom. I will try as suggested by you.

RE: How to convert dictionary to CDT?

Brinda — Mon, 08 Jan 2018 05:04:31 GMT

Thank you Benjamin. I created an expression rule and called it in the interface where I am giving address as input. Now I am able to get the latitude and and longitude for the given address.

RE: How to convert dictionary to CDT?

malcolm.ross — Mon, 08 Jan 2018 00:40:20 GMT

It would first be most efficient to run the fromJson once for your entire JSON string instead of calling it multiple times..

Like this

load(
local!googleMapsValue: a!fromJson( {your JSON string} ),
................

Then declare a local variable of the desired CDT type using type! to create a new value of the desired CDT type

'type!{urn:com:appian:types:{NAMESPACE}}{CDT NAME}'()

If you are using 17.4, then you will get an autosuggest when you type type! to pick your desired CDT.

Once you have your value of type declared, then start filling in the values. like

load(
local!googleMapsValue: a!fromJson( {your JSON string} ),
local!CDTwithLatLng: 'type!{urn:com:appian:types:{NAMESPACE}}{CDT NAME}'(

lat: local!googleMapsValue.results.geometry.location.lat
lng: local!googleMapsValue.results.geometry.location.lng
),

local!CDTwithLatLng
)

So essentially what you are doing is first converting the JSON to a data dictionary.

Then you are extracting the values you want using . notation and placing them in the desired CDT structure by declaring the variable to be of a certain type with type!

As mentioned, it is most efficient to only convert the JSON string once to data dictionary rather call fromJSON multiple times.

RE: How to convert dictionary to CDT?

benjamins — Mon, 08 Jan 2018 00:23:45 GMT

Similar to what was described above, doing this should work:

= with(
  local!result: rule!MY_INTEGRATION_RULE(),
  local!json: a!fromJson(local!result.result.body),
  local!lat: local!json.results.geometry.location.lat,
  local!lng: local!json.results.geometry.location.lng
)

Double check the json response. Start by just printing the response and then go down a level to see if it still returns valid responses. Continue until you get all the way to the lat an lon.

You may want to check how you are passing in the rule input into your integration object.

Ensure that it looks like

"https://maps.googleapis.com/maps/api/geocode/json?address=" & ri!address + "&key=<MY_KEY>

RE: How to convert dictionary to CDT?

Brinda — Sun, 07 Jan 2018 13:53:37 GMT

Hi Jeromew,

In the integration I am using "GET" method and using parameters to pass address and key. I am not using body in my inputs.

But I am getting the result in dictionary.

When I try to change the result into JSON by using the code suggested by you, it is throwing an error as follows:

Expression evaluation error at function a!fromJson [line 9]: Error evaluating function fn!fromjson_appian_internal : The jsonText parameter must not be null or empty.

Kindly let me know why I am getting the error and how can get the latitude and longitude?

RE: How to convert dictionary to CDT?

jeromew — Sat, 06 Jan 2018 21:36:45 GMT

Hi Brinda,

You should be able to extract the information like this:

/* change the result into JSON and get the relevant result body*/
local!lat: a!fromJson({your variable}.body.results.geometry.location.lat),
local!lng: a!fromJson({your variable}response.body.results.geometry.location.lng)