enumerate

RE: enumerate

Mike Schmitt — Tue, 13 Sep 2022 12:12:39 GMT

@stewart: 😆

RE: enumerate

kavitar298810 — Tue, 13 Sep 2022 12:02:08 GMT

RE: enumerate

Stewart Burchell — Tue, 13 Sep 2022 12:01:57 GMT

Well Mike Schmitt, nostalgia isn't what it used to be!

RE: enumerate

Mike Schmitt — Tue, 13 Sep 2022 11:56:26 GMT

This is a 4.5-year-old post...

RE: enumerate

kavitar298810 — Tue, 13 Sep 2022 05:04:13 GMT

If you want to write 5 in an enum, so you will get that output

If you can change it so you will get the same output as this

RE: enumerate

Amit Mishra — Thu, 04 Jan 2018 11:04:38 GMT

Your expression means- index({10,30,40,50,60,70},{0,1,2,3,4},{}) but problem is with third argument {}.
Better use a default value. You'll get desire output.
like - index({10,30,40,50,60,70},{0,1,2,3,4},0) will give you output- 0,10, 30,40,50

Regards,
Amit

RE: enumerate

Ravi Roshan — Wed, 03 Jan 2018 08:08:10 GMT

try using in this way:

apply(index({10,30,40,50,60,70},_,{}),enumerate(5))

This will give you proper result. For the 0th index it will not return anything.

RE: enumerate

annap — Wed, 03 Jan 2018 07:27:32 GMT

The problem is not in enumerate, it is in third parameter of "index" function. Don't pass null array. problem will be solve.

RE: enumerate

jacobm579 — Tue, 02 Jan 2018 18:22:20 GMT

Hey ganeshbabuj,

I think you may have a typo and just wanted to clarify. You say that index({10,30,40,50,60,70},enumerate(5),{}) returns 20 but there is no 20 in the given list. Did you mean to write that index({10,20,30,40,50,60,70},enumerate(5),{}) is returning 10; 20; 20; 30; 40?

This is the result that I got when I ran it.

I believe it has something to do with casting {} to an integer. I replaced {} with an integer and it worked as intended. It also works with null.

Thanks,
Jake

RE: enumerate

Vinay Kumar Rai — Tue, 02 Jan 2018 12:24:09 GMT

Hi,

enumerate(5) : returns : {0,1,2,3,4},

{10,30,40,50,60,70} : the Index of 10 is 1, 30 is 2 ans so on ,

INDEX : Has three parameters (array, index, default)

Note: the default value should not be array type

index({10,30,40,50,60,70},enumerate(5),null)

index({10,30,40,50,60,70},{0,1,2,3,4},null)

Returns: null,10,30,40,50

Note : Array start with 1 not 0

RE: enumerate

Shyam Bommakanti — Tue, 02 Jan 2018 12:19:06 GMT

enumerate(n) returns a list of integer numbers from 0 through n-1
enumerate(0) returns empty number list {}.
enumerate(1) returns {0}
enumerate(2) returns {0,1}
enumerate(3) returns {0,1,2}
enumerate(4) returns {0,1,2,3}
and so on.

In your example the index is not returning as expected.
Enumerate returns integer list starting from 0 and array/list index starts from 1 in Appian. When index() gets invalid index (<=0) is returns whatever listed as default value.
index({10,20,30,40,50,60,70},enumerate(5),{}) = index({10,20,30,40,50,60,70},{0,1,2,3,4},{}) returning invalid list of numbers {10,20,20,30,40}
index({10,20,30,40,50,60,70},enumerate(5) + 1,{}) = index({10,20,30,40,50,60,70},{1,2,3,4,5},{}) returning valid list of numbers {10,20,30,40,50}
index({10,20,30,40,50,60,70},enumerate(5),1) = index({10,20,30,40,50,60,70},{0,1,2,3,4},1) returning valid list of numbers {1,10,20,30,40}

index({10,20,30,40,50,60,70},enumerate(5),null) returns valid list of numbers {null,10,20,30,40}

{10,20,30,40,50,60,70} is auto casted to List of Number (Integer) where a {} is casted to List of Variant. When returning index always returns the type array input. Merging list of variant and integer ending up with unexpected list.