How to get CDT elements as value

RE: How to get CDT elements as value

Siva — Wed, 19 Sep 2018 06:45:32 GMT

Hi Nidhi,

As mentioned by Amit,

Create an expression rule and pass inputDataType(any type) as 'type!{urn:com:appian:types}employee_CDT'()

if(
rule!APN_isEmpty(
ri!inputDataType
),
"",
stripwith(
split(
ri!inputDataType,
"=,"
),
"[=]"
)
)

Thanks
Siva

RE: How to get CDT elements as value

nidhim855 — Wed, 19 Sep 2018 05:37:23 GMT

Thank You Ketan.

RE: How to get CDT elements as value

nidhim855 — Wed, 19 Sep 2018 05:36:54 GMT

Thank You . Its really helped me.

RE: How to get CDT elements as value

Ketan Patel — Tue, 18 Sep 2018 15:35:53 GMT

If it is an Oracle DB - you can directly use query DB smart service to get column names and use it as label:

select COLUMN_NAME from ALL_TAB_COLUMNS where TABLE_NAME='MyTableName';

I would say it is not the best way but straight forward rather.

RE: How to get CDT elements as value

amitm9 — Tue, 18 Sep 2018 12:49:09 GMT

'type!{urn:com:appian:types}employee_CDT'()
--- instead of employee_CDT you can use any CDT name for which you would like to get elements. Remember "namespace" of your CDT should be the same, if different then change accordingly. Thanks

RE: How to get CDT elements as value

amitm9 — Tue, 18 Sep 2018 12:44:22 GMT

Hi Nidhi,

Try using below logic.

load(
local!CDTFields: split(stripwith(tostring('type!{urn:com:appian:types}employee_CDT'()),"[=] "), ","),

{ local!CDTFields}

)

this will give you all elements of your CDT "employee_CDT". If you want to remove/hide any column, lets say default "id" column. then use difference function. As below code.

load(
local!CDTFields: split(stripwith(tostring('type!{urn:com:appian:types}employee_CDT'()),"[=] "), ","),

{ difference(local!CDTFields,"id") }

)