How to join 2 of the same CDTs/DictionaryI

RE: How to join 2 of the same CDTs/DictionaryI

sagare4545 — Wed, 25 Jun 2025 14:33:16 GMT

Yup :) .Just adding options.. if someone needs and lands to this page like me.

RE: How to join 2 of the same CDTs/DictionaryI

Mike Schmitt — Wed, 25 Jun 2025 12:57:18 GMT

This thread is almost 6 years old... -_-

RE: How to join 2 of the same CDTs/DictionaryI

sagare4545 — Wed, 25 Jun 2025 12:32:04 GMT

Below should also work for dictionary

local!dict1: {SOURCE_NAME: "Test", DESIGN_TYPE: "Something", PHASE: "AnotherThing"},

local!dict2: {SOURCE_NAME: "Test2", DESIGN_TYPE: "Something2", PHASE: "AnotherThing2"},

local!finalDict:{local!dict1,local!dict2},

local!finalData:a!flatten(local!finalDict)

RE: How to join 2 of the same CDTs/DictionaryI

ians — Wed, 03 Jul 2019 15:59:10 GMT

Thank you so much! This worked 🙂!

RE: How to join 2 of the same CDTs/DictionaryI

ankitab0001 — Wed, 03 Jul 2019 00:18:08 GMT

Hi ians

Try something like this

load(
  
 local!cdt1: {SOURCE_NAME: "Test", DESIGN_TYPE: "Something", PHASE: "AnotherThing"},

local!cdt2: {SOURCE_NAME: "Test2", DESIGN_TYPE: "Something2", PHASE: "AnotherThing2"},

local!cdt3: {SOURCE_NAME: "Test3", DESIGN_TYPE: "Something3", PHASE: "AnotherThing3"},

local!finalCdt:{local!cdt1,local!cdt2,local!cdt3},



'type!{http://www.test.com/test/}CM_CLAIM_TYPE'(
  SOURCE_NAME: joinarray({local!finalCdt.SOURCE_NAME},";"),
  DESIGN_TYPE:joinarray({local!finalCdt.DESIGN_TYPE},";"),
  PHASE:joinarray({local!finalCdt.PHASE},";")
)

)

cdt1,cdt2,cdt3 is of type CM_CLAIM_TYPE. Define a rule input of "finalCdt" and you can pass as many number of cdts to that rule input

Let me know if you have any queries.