Replace zero from an Integer array

RE: Replace zero from an Integer array

Mike Schmitt — Tue, 21 Jul 2020 14:46:25 GMT

Out of curiosity, why not use something more simple like, "if(fv!item = 0, index(local!values, fv!index+1, 0), fv!item)"? Granted, I haven't tested either way, just my quick-glance impression. I don't immediately see why we need to involve ldrop(), for example.

Edit: i missed the requirement that if the next value is zero then it should forward-seek until it finds the first nonzero value. I'll just go ahead and retract my objection ;-)

RE: Replace zero from an Integer array

shilpas0003 — Tue, 21 Jul 2020 13:38:40 GMT

Thank you Stefan!

This is a part of business requirement where we need to replace 0 with next amount value.

RE: Replace zero from an Integer array

Stefan Helzle — Tue, 21 Jul 2020 13:18:25 GMT

a!localVariables(
  local!values: {1,2,3,0,0,10,15,0,14,0},
  a!forEach(
    items: local!values,
    expression: if(
      fv!item = 0,
      index(
        /* Only take values after the current one */
        ldrop(local!values, fv!index - 1),
        /* Find the first not being zero */
        /* where() evaluates zero as false and >0 as true */
        index(where(ldrop(local!values, fv!index - 1)), 1, 0),
        fv!item
      ),
      fv!item
    )
  )
)

This should do it. May I ask what the use case is?