RE: Splitting Array based on condition

Peter Lewis — Mon, 21 Dec 2020 16:40:59 GMT

For something like this, I usually like to separate what you need into distinct steps. The main things that you want to do here are to (1) create a list of distinct values for the employeeID and (2) construct a new list based on these values that matches the original data.

The first step usually involves the union() function. This function allows you to get a unique list of values by defining a union against an empty array.

Then, the second step requires you to loop over the list of values and match the other attributes with the corresponding employeeID. I usually use a combination of wherecontains() and index() to return the corresponding items here. Here's an example with some sample data:

a!localVariables(
  local!data: {
    a!map(
      employeeID: "employee.one",
      attribute: "abc"
    ),
    a!map(
      employeeID: "employee.one",
      attribute: "def"
    ),
    a!map(
      employeeID: "employee.two",
      attribute: "xyz"
    ),
    a!map(
      employeeID: "employee.two",
      attribute: "123"
    ),
    a!map(
      employeeID: "employee.three",
      attribute: "abcdef"
    )
  },
  local!uniqueEmployees: union(
    local!data.employeeID,
    touniformstring({})
  ),
  a!forEach(
    items: local!uniqueEmployees,
    expression: a!map(
      employeeID: fv!item,
      attributes: index(
        local!data.attribute,
        wherecontains(
          fv!item,
          local!data.employeeID
        ),
        {}
      )
    )
  )
)