Print number Patterns

RE: Print number Patterns

devendrad4614 — Tue, 24 Sep 2024 19:35:47 GMT

RE: Print number Patterns

Stefan Helzle — Tue, 24 Sep 2024 16:59:05 GMT

Put your individual strings into a list on maps using foreach, then use the todatasubset() function to sort by that field.

RE: Print number Patterns

devendrad4614 — Tue, 24 Sep 2024 16:55:00 GMT

Suppose we have array of of strings from A-Z which is randomly arranged so , how we can sort all the alphabet in ascending order?

RE: Print number Patterns

Stefan Helzle — Tue, 24 Sep 2024 15:03:10 GMT

[quote userid="290475" url="~/discussions/f/rules/21320/print-number-patterns/141017"]how to sort alphabets in appian ? [/quote]

What exactly are you asking for?

RE: Print number Patterns

devendrad4614 — Tue, 24 Sep 2024 14:16:45 GMT

how to sort alphabets in appian ?

RE: Print number Patterns

dineshkrishna — Tue, 11 Oct 2022 06:02:33 GMT

Thanks Harshit...

RE: Print number Patterns

dineshkrishna — Tue, 11 Oct 2022 06:02:13 GMT

Thanks Ujjwal

RE: Print number Patterns

Harshit Bumb (Appyzie) — Tue, 11 Oct 2022 05:45:43 GMT

The question is not relevant to this thread so I have answered your question on another thread here which seems to be more relevant - community.appian.com/.../what-is-the-difference-initiator-and-loggedinuser

RE: Print number Patterns

ujjwalr0002 — Tue, 11 Oct 2022 05:30:33 GMT

The process initiator is the person who has started the process model and the process designer is the person who has last published the process model.

https://docs.appian.com/suite/help/20.4/process-model-object.html#actor-properties

RE: Print number Patterns

dineshkrishna — Tue, 11 Oct 2022 05:09:46 GMT

can anyone Explain for difference between Process initiator and Process designer

RE: Print number Patterns

dineshkrishna — Mon, 10 Oct 2022 11:28:41 GMT

oh ok Abhishek...thank you

RE: Print number Patterns

Abhishek_Manjunath — Mon, 10 Oct 2022 08:26:44 GMT

Those were the answers for the initial question:

For star pyramid:<I have used 2 loops, although i believe it can be reduced to one>

a!localVariables(
  local!input: 5,
  local!rows: where(mod(enumerate(5) + 1, 2)),
  local!star: a!forEach(
    items: local!rows,
    expression: concat(repeat(fv!item, "*"))
  ),
  local!space: reverse(enumerate(length(local!star))),
  a!forEach(
    items: local!space,
    expression: concat(rept("-", fv!item), local!star[fv!index])
  )
)

RE: Print number Patterns

dineshkrishna — Mon, 10 Oct 2022 07:51:32 GMT

Thanks for ur response Abhishek,

but i'm getting o/p as

"1"(Text)
"22"(Text)
"333"(Text)
"4444"(Text)
"55555"(Text)

"A"(Text)
"BB"(Text)
"CCC"(Text)
"DDDD"(Text)
"EEEEE"(Text)

but i need to get o/p as

*
* *
* * * * *
* * * * * * *

RE: Print number Patterns

Abhishek_Manjunath — Mon, 10 Oct 2022 07:43:31 GMT

We don't need to loop here:

Number:

rept(enumerate(5)+1, enumerate(5) + 1)

Alphabets:

a!localVariables(
  local!data: { "A", "B", "C", "D", "E" },
  rept(
    index(local!data, enumerate(5) + 1, null),
    enumerate(5) + 1
  )
)

RE: Print number Patterns

dineshkrishna — Mon, 10 Oct 2022 07:04:38 GMT

Hi Harshit,

Thanks for your response, just to know to get better clarity in functions, if you know logic please let me know

Thanks & Regards

Dinesh

RE: Print number Patterns

Harshit Bumb (Appyzie) — Mon, 10 Oct 2022 07:00:18 GMT

Why would you want to do that in Appian?

RE: Print number Patterns

dineshkrishna — Mon, 10 Oct 2022 06:59:05 GMT

How to do for Star/Hill program

* * *

* * * * *

logic input will be (Rows * 2 -1)

for eg 1st Row... 1*2-1=1 star

2nd Row 2*2-1=3 stars

3rd Row 3*2-1=5 stars

please suggest the logic

RE: Print number Patterns

shukurs0001 — Fri, 09 Sep 2022 19:45:58 GMT

a!localVariables(
  local!stringList: {"A","B","C","D","E"},
  a!forEach(
    items: enumerate(length(local!stringList)),
    expression:joinarray(repeat(fv!index,local!stringList[fv!index])," ")
  )
)

RE: Print number Patterns

shukurs0001 — Fri, 09 Sep 2022 19:37:20 GMT

a!forEach(
  items: enumerate(5),
  expression:joinarray(repeat(fv!index,fv!index)," ")
)

RE: Print number Patterns

viratyogi — Mon, 21 Mar 2022 04:30:49 GMT

Hi please refer to the below code, just replace the list with the desired input

a!localVariables(
  local!alphabet: { "A", "B", "C", "D", "E" },
  a!forEach(
    items: local!alphabet,
    expression: fn!joinarray(
      fn!repeat(
        fv!index,
        fv!item
      )
    )
  )
)

RE: Print number Patterns

sairohitd054766 — Sat, 19 Mar 2022 15:38:09 GMT

a!flatten(
a!forEach(
items: enumerate(5) + 1,
expression: { joinarray(repeat(fv!index, fv!item), "") }
)
)

RE: Print number Patterns

Stewart Burchell — Wed, 30 Jun 2021 08:45:13 GMT

Here you would need to effectively perform a substitution of the number that the previous example has been using with the relevant character:

a!localVariables(
  local!alphabet: {"A","B","C","D","E"},
  local!list: fn!enumerate(ri!myNumber) + 1,
  a!forEach(
    items: local!list,
    expression: fn!joinarray(fn!repeat(fv!item, fn!index(local!alphabet,fv!item,"?")))
  )
)

RE: Print number Patterns

madhukiran.vadlamudi — Wed, 30 Jun 2021 08:39:13 GMT

Hi stewart,

Your solution helps.But what if we have String in that place.

CCC

DDDD

RE: Print number Patterns

Stewart Burchell — Wed, 30 Jun 2021 07:55:21 GMT

fn!joinarray(fn!repeat(ri!myNumber, ri!myNumber))

Brief explanation:

ri!myNumber is the rule input to the expression, of type Integer.

fn!repeat() generates a list. It takes two parameters:

times
input

so here we are generating a list, the length of which is defined by the value of ri!myNumber, and the value of each item is also ri!myNumber

Since your output appears to be a a single string, the fn!joinarray is taking the list and collapsing it into a single value.

If you're actually wanting ALL of the outputs you've defined then you'll need to take the ri!myNumber, generate a list of the numbers from 1 to that number, and then use that list to iterate over the same pattern as expressed in the first code sample, like this:

a!localVariables(
  local!list: fn!enumerate(ri!myNumber) + 1,
  a!forEach(
    items: local!list,
    expression: fn!joinarray(fn!repeat(fv!item, fv!item))
  )
)

Now you have a general purpose Expression which you can pass any number and get the output to conform to the pattern of the example you provided. If you pass the value 5 to the new code you get this output:

Note: if you need the output to be a list of integer you'll have to use the fn!tointeger() to cast from text to integer.