Need Help on Expression Rule!!

RE: Need Help on Expression Rule!!

Mike Schmitt — Thu, 11 May 2023 12:49:01 GMT

Or like

a!localVariables(
  local!bankruptcy: {"Chapter1", "Chapter1", "Chapter3", "Chapter4"},
  local!creditPublicRecord: { "Test", "Chapter1", "Chapter2", "Other" },
  
  length(wherecontains(local!creditPublicRecord, local!bankruptcy))
)

RE: Need Help on Expression Rule!!

sanchitg0002 — Thu, 11 May 2023 12:31:56 GMT

Is this what you need?

a!localVariables(
  local!bankruptcy: {"Chapter1", "Chapter1", "Chapter3", "Chapter4"},
  local!creditPublicRecord: { "Test", "Chapter1", "Chapter2", "Other" },
  a!forEach(
    local!creditPublicRecord,
    a!map(
      item: fv!item,
      count:count(where({fv!item} = local!bankruptcy))
    )
  )
)

RE: Need Help on Expression Rule!!

Stefan Helzle — Thu, 11 May 2023 11:41:55 GMT

Is this like an intersection of the two lists of values? If yes, there is an intersection function in Appian. Then count the items in the result.

RE: Need Help on Expression Rule!!

Shaik Gousi — Thu, 11 May 2023 11:40:14 GMT

I have to compare each and every value of creditPublicRecord with the constant values of bankruptcy.

for example from the above snap,

local!creditPublicRecord has one value(judgement) and we have to check if that "judgement" matches with the bankruptcy value and if it matches then we need to count the number of matches. As there is no judgement in the bankruptcy so count is "0"

If local!creditPublicRecord has these values{"judgement","BankruptcyChapter11","BankrptcyChapter7","Other"} then we have to check how many times the values of local!bankruptcy matches the values of local!creditPublicRecord.

RE: Need Help on Expression Rule!!

Harshit Bumb (Appyzie) — Thu, 11 May 2023 11:32:29 GMT

You can compare both of these just by using the = operator. Try local!bankruptcy = local!creditPublicRecord and it will give you the result. If you want to compare them in any other way, then please mention it.