RE: Reverse a String without using reverse function

Mike Schmitt — Fri, 31 Jan 2025 15:19:52 GMT

Stefan's elegant tiny answer got me thinking about what the "elegant but somewhat more verbose" answer might be. Once again we can rely on a!forEach() and the dataSubset sort. The advantage with this approach is it could potentially handle use cases with a little more nuance if needed.

a!localVariables(
  local!sortMap: a!forEach(
    enumerate(len(ri!text))+1,
    
    a!map(
      index: fv!item,
      currentLetter: ri!text[fv!item]
    )
  ),
  
  local!sortedSet: todatasubset(
    arrayToPage: local!sortMap,
    pagingConfiguration: a!pagingInfo(1, -1, a!sortInfo(field: "index", ascending: false()))
  ).data,
  
  concat(local!sortedSet.currentLetter)
)

RE: Reverse a String without using reverse function

tanujd6440 — Fri, 31 Jan 2025 15:18:44 GMT

Thanks, I got to learn new way of problem solving

RE: Reverse a String without using reverse function

Stefan Helzle — Fri, 31 Jan 2025 15:11:39 GMT

No recursion required

ri!text[len(ri!text) - enumerate(len(ri!text))]