Conditionally displaying data in grid

RE: Conditionally displaying data in grid

Mike Schmitt — Mon, 07 Jun 2021 13:44:07 GMT

You would need to remove the "_19r1" from the end of the a!gridField rule, then change some of the components. The columns would need to be changed to use a!gridColumn() instead of a!gridTextColumn(), and these would get their data by directly referencing fv!row. I recommend first making a copy of the code for the original grid and trying to changeover the copy.

RE: Conditionally displaying data in grid

Stefan Helzle — Mon, 07 Jun 2021 09:59:25 GMT

Which version of Appian? Did you check the docs?

https://docs.appian.com/suite/help/21.2/SAIL_Recipes.html

Did you already try/test something? What went wrong?

RE: Conditionally displaying data in grid

apoorvam — Mon, 07 Jun 2021 09:53:52 GMT

Hi, thank you. Can you please give me an example on how to do that?

RE: Conditionally displaying data in grid

Mike Schmitt — Sat, 05 Jun 2021 15:40:52 GMT

I strongly recommend you to upgrade this grid to use the 19.2+ version of a!gridField() - this upgraded version makes it substantially easier to do row-by-row conditionality like what you're saying you need. In the deprecated version you're using, it requires looping over the data subset and doing your conditionality within the loops, which is doable but cumbersome and far more easily prone to errors.

RE: Conditionally displaying data in grid

Stefan Helzle — Sat, 05 Jun 2021 14:54:21 GMT

https://codeblog.jonskeet.uk/2012/11/24/stack-overflow-question-checklist/

Would you please explain what the question is, what did you try and what failed. Code snippets, screen shots.