interface within interface

RE: interface within interface

ZAINAB — Tue, 23 May 2023 08:08:36 GMT

Thank you ,It worked

RE: interface within interface

shoaib.akhtar — Mon, 22 May 2023 20:25:41 GMT

Try using this code, I believe this will suites your use case with showWhen property,

PS: you can use if else for the same scenario, just stack the sectionLayouts (Interface1, Interface2) and check or any one condition for pressed button.

a!localVariables(
  /*pressed button variable, default value have to be there for showing 1st interface*/
  local!pressedButton: "cancel",
  a!sectionLayout(
    contents: {
      /*Interface 1*/
      a!sectionLayout(
        contents: {
          a!boxLayout(
            label: "Some form",
            contents: {
              a!textField(label: "Comments", readOnly: true),
              a!textField(label: "Start Date", readOnly: true),
              a!textField(label: "End Date", readOnly: true),
              a!textField(label: "Emial", readOnly: true),
              
            }
          ),
          a!buttonLayout(
            primaryButtons: {
              a!buttonWidget(label: "approve"),
              a!buttonWidget(
                label: "reject",
                value: "reject",
                saveInto: local!pressedButton
              )
            },
            secondaryButtons: { a!buttonWidget(label: "cancel") }
          )
        },
        showWhen: local!pressedButton = "cancel"
      ),
      /*Interface 2*/
      a!sectionLayout(
        contents: {
          a!boxLayout(
            label: "Some form",
            contents: {
              a!paragraphField(label: "Comments", readOnly: true)
            }
          ),
          a!buttonLayout(
            primaryButtons: {
              a!buttonWidget(
                label: "cancel",
                value: "cancel",
                saveInto: local!pressedButton
              ),
              a!buttonWidget(label: "submit")
            }
          )
        },
        showWhen: local!pressedButton = "reject"
      )
    }
  )
)

RE: interface within interface

Mike Schmitt — Mon, 22 May 2023 14:23:45 GMT

If you're getting errors, it'd be helpful to post screenshots of the actual errors too, and describe what user action(s) lead to the error(s) in question, etc. Additionally it might be helpful for you to share your code (or at least relevant snippets) - and if you do, please be sure to use a Code Box.

RE: interface within interface

Mallepu Prashanth — Mon, 22 May 2023 13:21:11 GMT

You can achieve this using local variables by saving a value in local variable when user click on buttons and based on saved value in local variable you can apply it in showwhen in interfaces.

RE: interface within interface

davel001150 — Mon, 22 May 2023 13:16:30 GMT

Perhaps the simplest way is to create the "popup" as you call it as a separate component within it's own Interface object, then call it from the larger interface with a showWhen variable passed to it, or inside an if() function like if(local!commenting, rule!APP_commentInterface([parameters]), {}).

You'll probably need to explain the errors that are happening when you try showWhen for us to help you further from there.

RE: interface within interface

ZAINAB — Mon, 22 May 2023 13:10:58 GMT

yes , i have few basic knowledge , I tired doing it using showwhen but getting errors .can you please help

RE: interface within interface

laurensw — Mon, 22 May 2023 13:08:28 GMT

There are numerous ways to configure in accordance with these requirements within a single interface.
Have you followed any basic trainings yet in the Appian Academy?