paragraphfield in an interface is considering enters, tabs and spaces only as a value

RE: paragraphfield in an interface is considering enters, tabs and spaces only as a value

Sameer Ul Haq — Tue, 07 Jan 2025 10:17:06 GMT

Thanks! it helped to resolve the issue

RE: paragraphfield in an interface is considering enters, tabs and spaces only as a value

venkatrea696188 — Mon, 06 Jan 2025 15:32:33 GMT

Than wrap it with Stripwith function to remove the Enter key / Tab key character values.

 if(a!isNullOrEmpty(fn!trim(stripwith(local!X,char(10)))),"Please enter value","")

RE: paragraphfield in an interface is considering enters, tabs and spaces only as a value

Sameer Ul Haq — Mon, 06 Jan 2025 13:55:29 GMT

The input to the paragraph field is a enter key value. Since its not a visible text the field should through validation error.

For your validation expression

if(a!isNullOrEmpty(fn!trim(local!X)),"Please enter value","")

if the value of local!X is a enter key value the validation is still not firing. I want the validation error if any keyboard keys input to this paragraphfield is not a visible text to the user ex: enter key or space key or tab key inputs.

RE: paragraphfield in an interface is considering enters, tabs and spaces only as a value

venkatrea696188 — Mon, 06 Jan 2025 08:47:16 GMT

a!localVariables(
  local!X,
  {
  a!paragraphField(
    label: "Paragraph",
    labelPosition: "ABOVE",
    value: local!X,
    saveInto: {local!X},
    refreshAfter: "UNFOCUS",
    height: "MEDIUM",
    validations: {
      if(a!isNullOrEmpty(fn!trim(local!X)),"Please enter value","")
    }
  )
})

Your variable means where you ar5e storing the value of paragraph field . Can we see your code of the paragraph field

RE: paragraphfield in an interface is considering enters, tabs and spaces only as a value

Sameer Ul Haq — Mon, 06 Jan 2025 08:41:41 GMT

This is returning "" when i pass enter in place of Your Variable. Instead it should return "Please enter value"

RE: paragraphfield in an interface is considering enters, tabs and spaces only as a value

venkatrea696188 — Mon, 06 Jan 2025 07:45:25 GMT

Use trim function to remove extra spaces from value .

if(a!isNullOrEmpty(fn!trim(Your Variable)),"Please enter value","")