check an array has mix of values

Question

I have a condition where if a list contains only numbers as 10, i.e{10,10,10,10} I should return 1 else If list contains any numbers apart from 10 i.e{23,50,60} I have to return 0 else if that list contains mix of 10 and other numbers {10,23,45} then I have to return as 2. how can i write this in expression rule ?

Dude · Answer

Sidharth, please test the code with different lists like local!array1,local!array2,local!mixedArray .wherecontains(10, local!array1 ), 
 Replace the list name in the 
 a!localVariables( /* Values for testing*/ local!array1: { 10, 10, 10 }, local!array2: { 23, 50, 60 }, local!mixedArray: { 10, 23, 45 }, /*Checking results */ local!howManyOccurrances: wherecontains(10, local!array1 ), local!isArrayHasAll10s: length(local!array1) = length(local!howManyOccurrances), if( /*If list contains same number, return 1*/ local!isArrayHasAll10s, 1, /*If list contains different numbers along with given number , return 2*/ if( local!howManyOccurrances > 0, 2, /*If list contains different numbers than the given number , return 0*/ 0 ) ) ) 
 Note: When you use the logic in the implementation take care of the null checks