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100749 - no subject - I am trying to create a simple report of
Keith
over 10 years ago
I am trying to create a simple report of tasks that are late. I have it created. I created a filter set for the task status so you can see completed, assigned and accepted statuses. I want to also have a choice of Active. I have tried and tried and tried to make this happen and everything I try is not working.
I even created a rule with: called activeTask with =if(ri!taskStatus="Active",1,
if(ri!taskStatus="Assigned",1,
if(ri!taskStatus="Accepted",1,0)))
When I put try : =rule!activeTask(task_status()) I get all 0s in the report and no 1s.
What am I doing wrong?
I tried the if expression without a rule and it would not produce desired result either.
I don't want to be negative - but - simple things like this cause people not to want to learn how to do reports on their own.
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OriginalPostID-100749
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jesse.triplett
Appian Employee
over 10 years ago
Testing just that if statement with a text input seems to work fine. You could try using the like() or exact functions instead of the "=" , I think I've ran into something similar in the past. Have you used typename(typeof(ri!taskStatus)) to be sure the input is a text?
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Keith
over 10 years ago
Thank You for the tips - however - this did not work either. If I test the rule, I get the desired results. However the report is showing all 0s.
I changed the rule to be this.
=if(like(typename(typeof(ri!taskStatus)),"Active"),1,
if(like(typename(typeof(ri!taskStatus)),"Assigned"),1,
if(like(typename(typeof(ri!taskStatus)),"Accepted"),1,0)))
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Keith
over 10 years ago
I reported this worked - I am getting 0s even in the rule.
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jesse.triplett
Appian Employee
over 10 years ago
Sorry, I wasn't very clear. I meant try the like() function, and if that still doesn't work, double check that your input is being read as type text by having the expression just be typename(typeof(ri!taskStatus)) (no if statements at all, just checking that the output of this statement is the word "text" like expected.
if(like(ri!taskStatus,"Active"),1,
if(like(ri!taskStatus,"Assigned"),1,
if(like(ri!taskStatus,"Accepted"),1,0)))
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Keith
over 10 years ago
I even tried this... It worked in the rule - but - not in the report.
=if(like(tostring(ri!taskStatus),"Active"),1,
if(like(tostring(ri!taskStatus),"Assigned"),1,
if(like(tostring(ri!taskStatus),"Accepted"),1,0)))
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jesse.triplett
Appian Employee
over 10 years ago
Can you put in the code for your report?
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Keith
over 10 years ago
I do not see how to attach documents to this thread... I could email them to you.
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jesse.triplett
Appian Employee
over 10 years ago
There is a little "add attachments" paperclip in the bottom left corner of comment box. It appears once you start typing a comment. You could also past the code as a comment if it's not extremely long
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Keith
over 10 years ago
In a data field in the report - I am trying to show the results. I want to see a 1 or 0 by calling the rule.
Here is what I have in the report.
I just added the tostring to it now and it did not help.
=rule!activeTask(tostring(task_status()))
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jesse.triplett
Appian Employee
over 10 years ago
I'm not sure I understand --What is task_status(), a query rule? Does it have many statuses? Based on above it looks like rule!activeTask() is designed to accept a single value text as its input.
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