Most efficient way to replace null values in an array with 0?

pearlfranz

Certified Associate Developer

2 months ago

Currently using a!forEach and a!isNullOrEmpty to replace all null values in an array of integers with 0, but would love to learn the most efficient way to do so. Is apply() the way to go here? A different function? Many thanks for any and all help!

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Yogi Patel 2 months ago +2
Certified Associate Developer

The following code snippet might be helpful: a!localVariables( local!data: { 1, null, 0, 10, null }, local!updatedData: a!update( local!data, wherecontains(tointeger(null()), local!data), 0…
Peter Lewis 2 months ago +1
Appian Employee

Luckily the a!defaultValue() function does exactly what you're looking for! You just have to run it using a!forEach() to apply it to a list of values: a!localVariables( local!data: {1, 2, null, 4,…

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Kumar Agniwesh 2 months ago

If you just need to remove the null values from array then I would just to use remove(a!isnull,<array>).

But if you really have to replace then I would suggest not to use apply.
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Kumar Agniwesh 2 months ago

If you just need to remove the null values from array then I would just to use remove(a!isnull,<array>).

But if you really have to replace then I would suggest not to use apply.
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