Record Type: How to get record URL?

Question

I have a record for cases I have been creating in my app.On record grid when I click on caseIds a process model is invoked and flow is taken further.I want to create for url for different records based on user need. 
 For general records with summary view I am aware of the steps.How do I create for this scenario where I dont have summary view/related actions;just record grid with each id invoking new process. 
 Early response is appreciated thanks!

namratak0001 · Accepted Answer

Hi @priyas007, Please use STart process link to start a process model when user click on link. 
 https://docs.appian.com/suite/help/21.2/Start_Process_Link_Component.html

Madhusudan Sharma · Answer

Hi priyas0007 , as far as I understand your use case, you have a grid with a list of ids and you want to click on any of the id which will start a process along with some parameters. If my understanding is correct, you can utilize the following code to create links (however, it is not a best practice): 
 local!processLink: a!startProcessLink(
	processModel: cons!PROCESS_MODEL,
	processParameters: {
 key1: "param1",
 key2: "param2"
	}
)

local!link: a!safeLink(
	uri: cons!BASE_SITE_URL &
	"/start-process/" & index(local!processLink, "processModelOpaqueId", "") & "?parameters=" & index(local!processLink, "cacheKey", "")
) 
 If this doesn't help, could you please elaborate more about your requirement?

Record Type: How to get record URL?

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