Hello Everyone,
Can we achieve the below scenario using the forEach() function?
apply(
rule!appendTxt(
txt1: _,
txt2: _
),
merge(ri!txtArr1, ri!txtArr2)
)
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I believe what you would convert to forEach like this:
a!forEach( items: merge( ri!txtArr1, ri!txtArr2 ), expression: rule!appendTxt( txt1: fv!item[1], txt2: fv!item[2] ) )