Finding repeated items in an array

Question

Hi All, 
 I have an array 1,2,3,3,5,6 
 In this I want the repeated value which is 3 as output. 
 Can you please suggest which is the approach to be followed. 
 TiA 
 Harsha

Hema · Answer

Hi Harsha, 
 The below code snippet would be helpful to you, 
 load(
 local!data: {1,2,3,4,3,5,6,5,4,7},
 local!uniqueData: union(
 local!data,
 local!data
 ),
 reject(
 fn!isnull,
 a!forEach(
 items: local!uniqueData,
 expression: if(
 count(
 wherecontains(
 fv!item,
 local!data
 )
 ) > 1,
 fv!item,
 null
 )
 )
 )
) 
 Hope this helps! 
 
 Thanks, 
 Hema

aloks0189 · Answer

Hi Harsha, 
 Please find the code snippet demonstrating one of the approach to achieve your requirement below: 
 load(
 local!items_int: {1, 2, 3, 3, 4, 5, 4, 6},
 local!res,
 local!content: a!forEach(
 local!items_int,
 if(
 count(wherecontains(fv!item, local!items_int)) > 1,
 append(local!res, fv!item),
 append(local!res, {})
 )
 ),
 union(
 local!content,
 local!content
 )
)

/* OUTPUT: 3, 4 (Type: List of Number (Integer) ) */ 
 Hope this will help you.

Finding repeated items in an array

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