Rendering different values based on count function

Hi Jorge, I am not sure how the data in your tables is structured. But you could take a look at the sample code I have posted below and build your interface similarly:

with(
local!difficulty: {"HIGH", "MEDIUM", "LOW"},
local!randomItems: {
{task: "Build a pyramid", difficulty: "HIGH"},
{task: "Run a marathon", difficulty: "MEDIUM"},
{task: "Space travel", difficulty: "HIGH"},
{task: "Make coffee", difficulty: "LOW"}
},
a!forEach(
local!difficulty,
a!richTextDisplayField(
value: {
with(
local!indices: wherecontains(tostring(fv!item), touniformstring(local!randomItems.difficulty)),
{
a!richTextItem(
text: length(local!indices)&" "&fv!item&" items:",
),
char(10),
a!richTextBulletedList(
items: a!forEach(local!indices,
a!richTextItem(
text: index(index(local!randomItems, fv!item, {}), "task", {})
)
)
)
}
)
}
)
)
)

What if I have everything coming from the database?

You would just be replacing local!difficulty with your status constant (or a db query fetching ref data) and local!randomItems with a queryEntity that returns the items from the db.

You would just be replacing local!difficulty with your status constant (or a db query fetching ref data) and local!randomItems with a queryEntity that returns the items from the db.

It might be even easier if you have the data coming from a database. You can set up your query to aggregate on the field you want to compare to the constant. Then, you can use wherecontains to find the count of the associated data. Here's an example:

a!localVariables(
  local!query:a!queryEntity(
    entity: cons!<YOUR ENTITY HERE>,
    query: a!query(
      pagingInfo: a!pagingInfo(
        startIndex: 1,
        batchSize: -1
      ),
      aggregation: a!queryAggregation(
        aggregationColumns: {
          a!queryAggregationColumn(field: "<YOUR FIELD NAME HERE>", isGrouping: true),
          a!queryAggregationColumn(field: "id", aggregationFunction: "COUNT", alias: "count")
        }
      )
    )
  ),
  a!textField(
    label: "Count of Constant Value 1",
    readOnly: true,
    value: index(
      local!query.data.count,
      wherecontains(cons!<YOUR CONSTANT HERE>[1], touniformstring(local!query.data.<YOUR FIELD NAME HERE>)),
      0
    )
  )
)

In this example, I group by the field in the database to create the correct count. Then, I find whether that value exists in the output using wherecontains(). I can then find the associated count using the index() function.