Let us say I have array of dictionary {{id:1,name:"Faisal",department:"EEE"},{id:2,name:"Hasan",department:"E&E"}, {id:3,name:"Faridi",department:"E&C"}}
and I want to return id and name only based on department="EEE"
How can this be achieved using functions?
I have tried the below but not able to get the result and from this query I am able to return only one field.
a!localVariables( local!employees:{ {{id:1,name:"Faisal",department:"EEE"},{id:2,name:"Hasan",department:"E&E"}, {id:3,name:"Faridi",department:"E&C"}} }, a!forEach( items: local!employees, expression:if(fv!item.department="EEE",fv!item.name,{}) ))
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Use the expression part of a!forEach to construct a dictionary for each matching item.
expression: if( fv!item.department = "EEE", { id: fv!item.id, name: fv!item.name }, {} )
Mike is absolutely correct - that's the right way to do it. But one additional suggestion (if you're on 20.3 or later) is to use the a!map() function instead of reconstructing a dictionary. The map is basically the same as a dictionary except it doesn't break if you try to use dot notation and the field doesn't exist, so I've found that I prevent a lot of annoying bugs by using a map instead of a dictionary!
Here's an example using Mike's suggested expression:
expression: if( fv!item.department = "EEE", a!map( id: fv!item.id, name: fv!item.name ), {} )
oh right, i keep forgetting where the good places are to use a!map, like here.
Thank you very much Peter
Thank you very much Mike really