iterate the values and assign to user

Question

Im trying to write a expression rule where there are two ri variables , one ri variable has type list of users and other ri variable is of type list of numbers. 
 
 something like below 
 ri!users: {"abc","def"} 
 ri!numbers: {1,2,3,4,5,6,7} 
 
 i have a use case where i should need to receive list of dictionary in below format 
 { 
 user:"abc", 
 number:1 
 }, 
 { 
 user:"def", 
 number:2 
 }, 
 { 
 user:"abc", 
 number:3 
 }, 
 { 
 user:"def", 
 number:4 
 }, 
 { 
 user:"abc", 
 number:5 
 }, 
 { 
 user:"def", 
 number:6 
 } 
 . 
 . 
 . etc

Carlos Santander · Answer

This needs further work (extracting common rules, validations, etc.), but it should give you a good starting point: 
 
 = a!localVariables(
 local!userCount: count(ri!users),
 local!numberCount: count(ri!numbers),
 local!resultCount: max(local!userCount, local!numberCount),
 
 a!forEach(
 items: 1+enumerate(local!resultCount),
 expression: a!localVariables(
 local!userIdx: mod(fv!index, local!userCount),
 local!numberIdx: mod(fv!index, local!numberCount),
 {
 user: ri!users[if(local!userIdx=0, local!userCount, local!userIdx)],
 number: ri!numbers[if(local!numberIdx=0, local!numberCount, local!numberIdx)]
 }
 )
 )
)