How to replace first 5 digit with * and remaining number will same ?

minhajk0001 over 2 years ago

Hi,

I have to pass 10 digit number in the rule input, how to replace first 5 digit number with * and remaining 5 digit will same ?

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Stewart Burchell over 2 years ago +2
Appian Employee

This will achieve what you've expressed: fn!concat("XXXXX", fn!right(ri!myNumber, 5)) Note: it's best practice to encapsulate literals in constants so that a) their value can be maintained independently…
Acacio Barrado over 2 years ago +1

Hi there, There are multiple ways that you could achieve that, but you can try the code below to give you some idea: replace(1234567890,1,5,"*****") Just replace the numbers for your rule input.…

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0 Acacio Barrado over 2 years ago
Hi there,

There are multiple ways that you could achieve that, but you can try the code below to give you some idea:

replace(1234567890,1,5,"*****")

Just replace the numbers for your rule input.

Hope that helps.

Acacio B.
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0 Acacio Barrado over 2 years ago
Hi there,

There are multiple ways that you could achieve that, but you can try the code below to give you some idea:

replace(1234567890,1,5,"*****")

Just replace the numbers for your rule input.

Hope that helps.

Acacio B.
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Vote Up +1 Vote Down

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