How we will covert ("INDIA") TO {"I","N","D","I","A"}

Question

How we will covert ("INDIA") TO {"I","N","D","I","A"}. How we will write in expression rule?

Mike Schmitt · Answer

Let me introduce you to "code()", which splits any string into an array of the character codes. Then "char()" which, if applied to an array, provides the characters for those codes (but still in an array). 
 char(code("INDIA")) 
 Honestly with as much as certain people around here (*ahem*) obsess over coming up with the shortest-possible-code for things even at the sacrifice of any readability, I'm shocked nobody beat me to this Edit to add: I see Bejjenki included something similar (but, strangely, more verbose for some reason) in his "2nd way" above.

Richard Michaelis · Answer

Hi pd, my solution: a!forEach(
 items: enumerate(len("INDIA"))+1,
 expression:charat( "INDIA", fv!item)
) regards, Richard

davel001150 · Answer

char(code("INDIA")) 
 Lol, sorry Mike. Still need to know when you and Stephan sleep so I can try for 50 answers achievement.

How we will covert ("INDIA") TO {"I","N","D","I","A"}

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