Want to display numbers from 105

Could you please try the below code.

a!localVariables(
  local!data: 101 + enumerate(100),
  index(
    local!data,
    (enumerate(count(local!data)/5)+1)*5,
    {}
  )
)

its only showing those are divided by 5 i want to show that but as well after 150 i want to show 151,152,153,154,155,156,157,158,159 like this then after 160 again 165,170

Something like below?

a!localVariables(
  local!data: 101 + enumerate(100),
  local!indexesContains5: wherecontains(true(), find(5, local!data, 1) > 1),
  local!multipleOf5: (enumerate(count(local!data) / 5) + 1) * 5,
  sortintegerarray(
    index(
      local!data,
      union(
        local!multipleOf5,
        local!indexesContains5
      ),
      {}
    ),
    false()
  )
)

Its working Thank You!

a!localVariables(

local!test:a!forEach(

items: 101+enumerate(100),

expression:if(mod(fv!item,5)=0,fv!item,{}) ),

local!test

)

a!localVariables(
  local!data:a!forEach(
    items: enumerate(100)+101,
    expression: {if(mod(fv!index,5),{},fv!item),if(find(5,fv!item),fv!item,{})}
  ),
 union(local!data,local!data)
)

Hi

Once try it with this..

a!localVariables(
local!data: a!forEach(
items: enumerate(101)+100,
expression: append(if(find(5,fv!item),fv!item,{}),if(mod(fv!item,5),{},fv!item)),
),
local!uniqueData:union(local!data,local!data),
local!uniqueData
)

i just saw my work has the same error. tks 

papa's games

Nice challenge, but for what purpose? Below my approach.

{
  105 + enumerate(9) * 5,
  150 + enumerate(11),
  160 + enumerate(9) * 5,
}

Unknown said:

Nice challenge

indeed.

i was, also, wondering if this could be reduced to something more elegant/simple and I just came up with this:

(enumerate(20) + 21) * 5

Though of course a lot depends on unfilled assumptions - how long of a list do we need?  Are we assuming it ends at "200" or is that just an example ending point?