I need to create XML with the following pattern. <Root>

piyusha over 9 years ago

I need to create XML with the following pattern.

<Root>
<Entity type="Employee">
<EmployeeNumber/>
</Entity>
</Root>

I am using toxml function to convert the CDTs into XML. But here problem is with attribute of Entity element i.e. type="Employee"
How can we have the XSD with attributes(default value of type attribute will be "Employee") which can be imported with out any error. I tried with many annotations but it seems to be not working.

Could any please share the approach. Thanks

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0 kdimitrov over 9 years ago

Hi Piyusha,

You need to use the syntax for attributes as detailed in creating an XSD, such as: <xsd:attribute name="type" type="xsd:string"/>. It goes straight after </xsd:sequence> and will be available in the designer for use as well.
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0 kdimitrov over 9 years ago

Hi Piyusha,

You need to use the syntax for attributes as detailed in creating an XSD, such as: <xsd:attribute name="type" type="xsd:string"/>. It goes straight after </xsd:sequence> and will be available in the designer for use as well.
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