displayvalue function

In case, if the value of 1 in the first array always has A in the second array and the same pattern follows always, then you may do as follows:

repeat(
          fn!length(wherecontains(1,{1,2,3,1,4,1})),
          displayvalue(1,{1,2,3,1,4,1},{"A","B","C","A","D","A"},{})
)

Try this instead: index({"A","B","C","A","D","A"}, wherecontains(1, {1,2,3,1,4,1}), {})

Displayvalue is expecting only one entry in the corresponding array. This should work for you.

@pavani this is not the answer for your question. But you can learn more about displayvalue(). here is the scenario where you can use dispalyvalue()

Return a CDT from an Array that Contains a Field Value Matching Another Value

Use Case

You have an array of department CDTs saved to a process variable called pv!departments each containing a field called Id, and you want to retrieve the CDT with an Id value matching the value of a process variable.

Ingredients

displayvalue()
Process Variable: pv!departmentId (Integer)
Process Variable: departments (CDT Array)
Custom Data Type:

department (Text)
|- Id (Integer)
|- Address (Text)
Expression

displayvalue(pv!departmentId, pv!departments.Id, pv!departments, "none")
NOTE: To change the value that displays if the pv!departmentId doesn't match any department.Id values, modify the none text value as desired.