Hi,
I am trying to find out key column value and if it contain {3,9}, I want to show the specific column. But, I am encountering below error. Can someone advice what needs to be done.
Thanks in advance.
Could not display interface. Please check definition and inputs. Interface Definition: Expression evaluation error at function a!gridField [line 2]: Invalid types, can only act on data of the same type (Number (Integer), Record Field)
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Reference the record field like:
fv!row[recordtype!recordName.field]
I am getting the below error when I try use like fv!row[recordtype!recordName.field]
Could not display interface. Please check definition and inputs. Interface Definition: Expression evaluation error at function a!gridField [line 6]: Could not find variable 'fv!row'
fv!row is only available inside the "value" parameter. Making a whole column visible depending on the value of an individual cell also does not make that much sense.