TWO SUM

Certified Associate Developer

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

You can return the answer in any order.

 

Example 1:

Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].

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Parents
  • +1
    Certified Lead Developer

    a!localVariables(
      local!numbs: {2,7,11,15},
      local!target: 9,
      reject(
        a!isNullOrEmpty(_),
        a!forEach(
          items: local!numbs,
          expression: if(
            fv!item > local!target,
            null,
            wherecontains(local!target - fv!item, local!numbs)
          )
        )
      )
    )

    It works aside from Appian arrays index starting at 1.  Uses only 1 forEach loop, and should be able to handle multiple correct answers.  15 lines just like the other. =/

Reply
  • +1
    Certified Lead Developer

    a!localVariables(
      local!numbs: {2,7,11,15},
      local!target: 9,
      reject(
        a!isNullOrEmpty(_),
        a!forEach(
          items: local!numbs,
          expression: if(
            fv!item > local!target,
            null,
            wherecontains(local!target - fv!item, local!numbs)
          )
        )
      )
    )

    It works aside from Appian arrays index starting at 1.  Uses only 1 forEach loop, and should be able to handle multiple correct answers.  15 lines just like the other. =/

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