Creating single map from list of maps

What would this "conversion" look like? Just take the first one, or the last, or combine things somehow?

I have an output something like below, i would want to convert these 6 map items to single map and these field names are not static , field names can differ and are dynamic

Yes

it has key value pair and key are field names and value has associated value to it , i just need to merge into single map

a!localVariables(
  local!maps: {
    a!map(alpha: "a"),
    a!map(beta: 2),
    a!map(gamma: "three")
  },
  local!keys: a!flatten(
    a!forEach(
      items: local!maps,
      expression: a!keys(fv!item)
    )
  ),
  a!update(
    a!map(),
    local!keys,
    a!forEach(
      items: local!maps,
      expression: index(
        fv!item,
        a!keys(fv!item),
        null
      )
    )
  )
)

there are map inside map , because of that key will not fetch the key name , if i flatten complete array sets ,key wont be unique

example maps are attached and the error which i am getting is also been attached

I can't see how your data structure looks like, but I think you should be able to adapt my code to your needs. If you have a list of list of maps, it might be a good idea to put my code into a separate expression. Then use a foreach on the top level to iterate on each of the rows from the screenshot.

i will try to use it ,thanks for the help!

The above suggested code will give you the solution. You can use 'a!flatten()' to get a single list of map if you have map inside maps.

this would create an issue of duplicate key names

How can you create a single map with duplicate keys?

If you wish to modify the key names at run time then you can add additional logic after getting local!keys. 

I have added an additional local!modifiedKeys in Stefan's code

a!localVariables(
  local!maps: {
    a!map(alpha: "a"),
    a!map(beta: 2),
    a!map(beta: 3),
    a!map(gamma: "three"),
    a!map(gamma: "four"),
    a!map(gamma: "five")
  },
  local!keys: a!flatten(
    a!forEach(
      items: local!maps,
      expression: a!keys(fv!item)
    )
  ),
  local!modifiedKeys: a!forEach(
    items: local!keys,
    expression: a!localVariables(
      local!indexCount: count(
        wherecontains(
          tostring(fv!item),
          touniformstring(local!keys)
        )
      ),
      if(
        local!indexCount = 1,
        fv!item,
        concat(fv!item, fv!index)
      )
    )
  ),
  a!update(
    a!map(),
    local!modifiedKeys,
    a!forEach(
      items: local!maps,
      expression: index(fv!item, a!keys(fv!item), null)
    )
  )
)

Thanks for the solution, I was able to use Stefan’s code and resolved my issue yesterday 

Thanks for the solution, I was able to use Stefan’s code and resolved my issue yesterday