Is there away to control how a date value is displayed in a paging grid? The val

try using the fn!datetext() function... for example:
datetext(pv!myData, "MM/dd/yyyy hh:mm:ss z")
MM: Month
dd: day
yyyy: Year (2 or 4 digits are valid)
hh:Time in 12 hours format (use HH for 24 hour format)
mm: minutes
ss: seconds
z: timezone in standard format as defined by the system

Forgot to add, if used in a grid, you will need to use the apply function in the gridTextColumn, for example:
a!gridTextColumn(
...
data: apply(
fn!datetext(_, "MM/dd/yyyy hh:ss"),
index(local!gridData.data,"myDate",null),
...
)

I have also found that the text() function is a more robust substitute for the datetext() function in terms of its ability to gracefully accept null parameters.

Hi josephs,

This is pretty much possible even in 7.2

we can go with either of the below functions:
1) =text(todate(ri!dateTime),"dd/mmm/yyyy")
2) =index(split(ri!dateTime," "),1)

since its version 7.2, we need to create a dummy cdt same as the cdt which we want to show in paging grid with the dateTime fields as text. Now we need to desine the variable with the dummy CDT type in our process model.Then we need to save each column in this dummy cdt in a script task by apply any of the above functions to the "dateTime columns".This is because we need to show dateTime as Date in required Format in paging Grid.Now we can simply use the Dummy CDT to display the data in our paging grid.

hope this helps......Also find the screen shot of which i have created the scenario and displayed in a form