137567 - no subject - How can i get all the users with user ty

Hi Ricky. As far as i know, there is no direct Expression Function. But we can check a particular userTypeName by using User function Ex: user("ricky","userTypeName"). This will return Administrator or User. Hope this helps...........

You can create a group. Then create a membership rule (from the 'Rules' tab) for the group to "add users whose 'User Type' 'equals' 'Administrator' ".

..and with the group that include all Administrators in place you can retrieve all its users by doing something like this (where ADMINS_GROUP is a constant that points to that group you created using the suggestion from the user above)

=getdistinctusers(topeople(cons!ADMINS_GROUP))

Thank you pavithrac, Stevan and Eduardo :)

To determine the system admins, you can run the following expression:

=load(
local!designerUsers: getdistinctusers(getgroupbyname("Designers")),
local!adminUsers: apply(fn!isusersystemadministrator,local!designerUsers),
index(local!designerUsers,where(local!adminUsers),{})
)

The default Designers group contains all system admins by rule, but non-admin users can be added to the group so the second step is needed as a safety check.