For Each Issue

Hi sauravk,

As far as I know in expression we have fv!isLast which gives you the last iteration.I think it might work in your case.

Thanks,
ravalik

Will you be able to update my code for that . It would be great.

I'm guessing your code is just a snippet as it isn't syntactically correct. If you're able to post a snippet that is syntactically correct, someone might be able to help.

Hi sauravk,

Here is the code.Please have a look.
load(
local!a:{
"A","B","C"
},
local!b:{
"category1","category2","category3"
},
local!lastRowDetails: a!forEach(
items: local!a,
expression: {
with(
local!aitem:fv!item,
local!index:fv!index,
local!last:fv!isLast,
a!forEach(
items: local!b,
expression: {

if(
and(
fv!isLast = true(),
local!last = true()
),
local!aitem &" "&fv!item,
{}
)
}
)
)

}
),
a!flatten(local!lastRowDetails)

)

Thanks,
ravalik

Hi sauravk,

Here is the code.Please have a look.
load(
local!a:{
"A","B","C"
},
local!b:{
"category1","category2","category3"
},
local!lastRowDetails: a!forEach(
items: local!a,
expression: {
with(
local!aitem:fv!item,
local!index:fv!index,
local!last:fv!isLast,
a!forEach(
items: local!b,
expression: {

if(
and(
fv!isLast = true(),
local!last = true()
),
local!aitem &" "&fv!item,
{}
)
}
)
)

}
),
a!flatten(local!lastRowDetails)

)

Thanks,
ravalik

You really shouldn't ever do this:

and(
fv!isLast = true(),
local!last = true()
)

They are booleans for a reason, and should be treated as booleans! :)

and(
fv!isLast,
local!last
)