using if statements in interface

Question

Hi all, 
 I'm creating an interface that records and calculates the working hours for employees, the idea is if the working hours are less than 8 it should display: " Working hours are incomplete " , and if it was less than 0 it should display: " insert your working hours correctly please " 
 I made this expression, but when the value is less than 8 even it was less than 0 it always display : " Working hours are incomplete " 
 here's the expression: 
 { a!richTextItem( if( ri!WorkingHours = "8", "Working hours are complete", if( 8 > ri!WorkingHours > 0, "Working hours are not complete", if( ri!WorkingHours < 0, "insert working hours correctly please" ) ) ) )

Harshit Bumb (Appyzie) · Accepted Answer

Multiple conditions in Appian can be configured using or() & and() functions. 
 a!richTextDisplayField(
 value: {
 a!richTextItem(
 if(
 ri!WorkingHours = "8",
 "Working hours are complete",
 if(
 and(8 > ri!WorkingHours, ri!WorkingHours > 0),
 "Working hours are not complete",
 if(
 ri!WorkingHours < 0,
 "insert working hours correctly please",
 {}
 )
 )
 )
 )
 }
)

Amaan Shekh · Answer

try this 
 a!richTextDisplayField(
 value: {
 a!richTextItem(
 if(
 ri!WorkingHours = "8",
 "Working hours are complete",
 if(
 and(8 > ri!WorkingHours, ri!WorkingHours > 0),
 "Working hours are not complete",
 "insert working hours correctly please"
 
 )
 )
 )
 }
)

Harshit Bumb (Appyzie) · Answer

Ali Abdulqawi 
 I missed the third parameter in the last if. You can add an empty list there. I have updated the same code

Amaan Shekh · Answer

its because the third if only have two parameters in it if(
 ri!WorkingHours < 0,
 "insert working hours correctly please"
 ) we can remove this or can pass on more parameter as if(
 ri!WorkingHours < 0,
 "insert working hours correctly please",
 "working hours passed limit"
 ) , you can choose according to your use case

Ujjwal Rathore · Answer

Using the amazing match function. 
 a!richTextDisplayField(
 value: {
 a!richTextItem(
 a!match(
 value: ri!WorkingHours,
 equals: 8,
 then: "Working Hours are complete",
 whenTrue: and(ri!WorkingHours > 0, 8 > ri!WorkingHours),
 then: "Working hours are not complete",
 default: "insert working hours correctly please"
 )
 )
 }
)

Mike Schmitt · Answer

I'm not sure why it would be doing that - can you confirm what data type your ri!WorkingHours is? If the value was somehow technically "greater than 8" (like perhaps in the back-end storing a value of 8.001 for example) then it would fail the condition. To troubleshoot, maybe try wrapping "ri!workingHours" in the "value" parameter of a!match() in "tointeger()", and see if that changes anything. 
 Additionally, the truly correct way of using a!match would be that you only invoke ri!workingHours once, then refer to it as fv!value within the "whenTrue" parameter, when needed. The difference may appear cosmetic, though this means that if you format the value parameter (such as using "tointeger()"), then further references to the value will remain consistent.

using if statements in interface

Top Replies