Hi, I'm looking for a way to start a process by a given url, the process is now in a record action, in any case I can start it as process model, without any record action's relation because of I can send parameters to the process model. Any idea how to build this url?
Thanks in advance
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Appian does not support starting a process by a link.
Can you explain why you do not want to use the existing Appian features?
Thanks, but I think I got tha answer:
local!actionUrlPart: "/actions/ActionId", local!urlForRecord: a!urlForRecord( recordType: recordType!XXX targetLocation: site!SiteName.Page, identifier: 1 ), local!urlFinal: replace( local!urlForRecord, search("/summary",local!urlForRecord,1), 8, local!actionUrlPart ),
Hi eyleenm8832 ,
I am working on similar requirement, may I know how do you find the local!actionUrlPart for the higher environment. specifically when you do not have access to this related action due to action security in records.
TIA.
Sure,
You need to start the action in a new tab and check the URL and take only the "/action/uuid" part, in any case you need to have access to the record action, it's necessary for you to check the url and also execute the link.
okay, but for production URL you need to trigger the related action and .
1.I am working on fresh application so I wont actually have any records to action on.
2. Also, with the updated action security, we have restricted the Related action to concern user so I can not actually start the action from record.
any other way to find this out?
Hi,
The uuid of an object does not change between environments.
yeah, UUID would be unique, however I could understand that this is not UUID of any object. If it is which object's uuid is this?
This part is opaque Related Action Id for the related action, which I am able to only get if I have access to trigger that action.