enumerate

Question

Another technical question on how enumerate works. Can some one explain 
 index({10,30,40,50,60,70},enumerate(5),{}) 
 returns

10; 20; 20; 30; 40 
 Expected out 
 10; 20; 30; 40 
 But same works with below std code , but not sure why? 
 index({10,20,30,40,50,60,70},enumerate(5)+1,{}) 
 output :

10; 20; 30; 40; 50

Syntax 
 enumerate(n)

Returns a list of integer numbers from 0 through n-1 .

Returns : List of Number (Integer)

n (Number (Integer)): The number of integer numbers to return.

jacobm579 · Answer

Hey ganeshbabuj, I think you may have a typo and just wanted to clarify. You say that index({10,30,40,50,60,70},enumerate(5),{}) returns 20 but there is no 20 in the given list. Did you mean to write that index({10,20,30,40,50,60,70},enumerate(5),{}) is returning 10; 20; 20; 30; 40? This is the result that I got when I ran it. I believe it has something to do with casting {} to an integer. I replaced {} with an integer and it worked as intended. It also works with null. Thanks, Jake

annap · Answer

The problem is not in enumerate, it is in third parameter of "index" function. Don't pass null array. problem will be solve.

kavitar298810 · Answer

If you want to write 5 in an enum, so you will get that output

If you can change it so you will get the same output as this