Hi Forum If I had two text arrays, both with the same count() values,

load(
local!arr1: {"A","B","C","D"},
local!arr2: {"E","F","G","H"},

merge(local!arr1, local!arr2)
)

By doing this way the output will be of List of Variant - 4 items and each item will have list of strings with 2 items. example "A", "E". However if you want all 8 items in one list, you can use a!flatten function to your output, it will give you output as List of Text String - 8 items (A,E,B,F,C,G,D,H)

load(
local!arr1: {"A","B","C","D"},
local!arr2: {"E","F","G","H"},

merge(local!arr1, local!arr2)
)

By doing this way the output will be of List of Variant - 4 items and each item will have list of strings with 2 items. example "A", "E". However if you want all 8 items in one list, you can use a!flatten function to your output, it will give you output as List of Text String - 8 items (A,E,B,F,C,G,D,H)