Hi Forum If I had two text arrays, both with the same count() values,

Question

Hi Forum

If I had two text arrays, both with the same count() values, is there an easy way to concatenate the two arrays so that their respective indexes would match up?

eg

Array 1: {A;B;C;D}
Array 2: {E;F;G;H}

The resulting array would be {AE;BF;CG;DH}

I've tried saving ((pv!array1)&(pv!array2)) into a new array with no success.

Any help would be greatly appreciated! ...

Ravi Roshan · Answer

load( local!arr1: {"A","B","C","D"}, local!arr2: {"E","F","G","H"}, merge(local!arr1, local!arr2) ) 
 By doing this way the output will be of List of Variant - 4 items and each item will have list of strings with 2 items. example "A", "E". However if you want all 8 items in one list, you can use a!flatten function to your output, it will give you output as List of Text String - 8 items (A,E,B,F,C,G,D,H)

Ravi Roshan · Answer

load( local!arr1: {"A","B","C","D"}, local!arr2: {"E","F","G","H"}, local!totalCount: length(local!arr1), local!countArray: enumerate(local!totalCount) +1, a!forEach( items: local!countArray, expression: local!arr1[fv!index] &" " & local!arr2[fv!index] ) ) 
 Above solution will give you the output as List of Text String - 4 items as {"A E", "B F", "C G", "D H" }.