Splitting an array

May I ask why you need to do that?

Tried to reduce the lines of code a bit ...

a!localVariables(
  local!list: floor(rand(23)*100),
  local!max: 5,
  
  a!forEach(
    items: enumerate(ceiling(length(local!list) / local!max)),
    expression: a!forEach(
      items: fv!item * local!max + 1 + enumerate(local!max),
      expression: index(local!list, fv!item, {})
    )
  )
)

Hi Stefan,

I have 2 Questions.

1. There are 2 numbers. one start number and one end number. in between those numbers, we have to find the one number?

example: my start number is 100, end number is 200

find number : 5

output: 105, 115, 125, 135, 145, 150,151,152,153,154,155,156,157,158,159,165,175,185,195

2. my input number is 5

output : 1  22  333  4444

can you pls give the code for these 2 questions?

Here is the answer for 1 Question :- 

a!localVariables(
  local!xyz: 101 + enumerate(100),
  local!where_five: a!forEach(
    items: local!xyz,
    expression: like(tostring(fv!item), "*5*")
  ),
  index(
    local!xyz,
    wherecontains(true, local!where_five),
    {}
  )
)

Q2.

a!forEach(
  enumerate(5),
  substitute(
    tostring(
      repeat(fv!index,fv!item)
    ),
    "; ",
    ""
  )
)

1)

a!localVariables(
  local!xyz: 101 + enumerate(100),
  index(
    local!xyz,
    where(like(touniformstring(local!xyz), "*5*"))
  )
)

2)

a!forEach(
  items: enumerate(5),
  expression: rept(fv!item, fv!item)
)

1)

a!localVariables(
  local!xyz: 101 + enumerate(100),
  index(
    local!xyz,
    where(like(touniformstring(local!xyz), "*5*"))
  )
)

2)

a!forEach(
  items: enumerate(5),
  expression: rept(fv!item, fv!item)
)

just an alternate approach for 1)

a!localVariables(
local!num: 101 + enumerate(100),
reject(
fn!isnull,
if(mod(local!num, 5) = 0, local!num, {})
)
)

for 2) i think we dont need to loop:

rept(enumerate(5)+1, enumerate(5) + 1)