Print number Patterns

fn!joinarray(fn!repeat(ri!myNumber, ri!myNumber))

Brief explanation:

ri!myNumber is the rule input to the expression, of type Integer.

fn!repeat() generates a list. It takes two parameters: 

• times
• input

so here we are generating a list, the length of which is defined by the value of ri!myNumber, and the value of each item is also ri!myNumber

Since your output appears to be a a single string, the fn!joinarray is taking the list and collapsing it into a single value.

If you're actually wanting ALL of the outputs you've defined then you'll need to take the ri!myNumber, generate a list of the numbers from 1 to that number, and then use that list to iterate over the same pattern as expressed in the first code sample, like this:

a!localVariables(
  local!list: fn!enumerate(ri!myNumber) + 1,
  a!forEach(
    items: local!list,
    expression: fn!joinarray(fn!repeat(fv!item, fv!item))
  )
)

Now you have a general purpose Expression which you can pass any number and get the output to conform to the pattern of the example you provided. If you pass the value 5 to the new code you get this output:

Note: if you need the output to be a list of integer you'll have to use the fn!tointeger() to cast from text to integer.

fn!joinarray(fn!repeat(ri!myNumber, ri!myNumber))

Brief explanation:

ri!myNumber is the rule input to the expression, of type Integer.

fn!repeat() generates a list. It takes two parameters: 

• times
• input

so here we are generating a list, the length of which is defined by the value of ri!myNumber, and the value of each item is also ri!myNumber

Since your output appears to be a a single string, the fn!joinarray is taking the list and collapsing it into a single value.

If you're actually wanting ALL of the outputs you've defined then you'll need to take the ri!myNumber, generate a list of the numbers from 1 to that number, and then use that list to iterate over the same pattern as expressed in the first code sample, like this:

a!localVariables(
  local!list: fn!enumerate(ri!myNumber) + 1,
  a!forEach(
    items: local!list,
    expression: fn!joinarray(fn!repeat(fv!item, fv!item))
  )
)

Now you have a general purpose Expression which you can pass any number and get the output to conform to the pattern of the example you provided. If you pass the value 5 to the new code you get this output:

Note: if you need the output to be a list of integer you'll have to use the fn!tointeger() to cast from text to integer.

Hi stewart,

Your solution helps.But what if we have String in that place.

like 

A

BB

CCC

DDDD

Here you would need to effectively perform a substitution of the number that the previous example has been using with the relevant character:

a!localVariables(
  local!alphabet: {"A","B","C","D","E"},
  local!list: fn!enumerate(ri!myNumber) + 1,
  a!forEach(
    items: local!list,
    expression: fn!joinarray(fn!repeat(fv!item, fn!index(local!alphabet,fv!item,"?")))
  )
)

a!localVariables(
  local!stringList: {"A","B","C","D","E"},
  a!forEach(
    items: enumerate(length(local!stringList)),
    expression:joinarray(repeat(fv!index,local!stringList[fv!index])," ")
  )
)