find duplicate characters count in a string

Question

input: "Banana", 
 output: "B---------------1" , "aaa---------------3", "nn---------------2" 
 any one try it anthor way .. 
 { 
 a!localVariables( local!data: "Banana", local!len: len(local!data), local!merge: union( a!forEach( items: enumerate(local!len) + 1, expression: local!data[fv!index] ), a!forEach( items: enumerate(local!len) + 1, expression: local!data[fv!index] ) ), local!all: a!forEach( items: enumerate(local!len) + 1, expression: local!data[fv!index] ), a!forEach( items: local!merge, expression: index( local!data, wherecontains(fv!item, local!all), {} ) & "---------------" & count(wherecontains(fv!item, local!all)) ) ) 
 }

Mike Schmitt · Answer

Here's a somewhat different implementation - slightly longer but more focused on abstracting the individual steps on easier-to-understand local variable definitions, and without a need to iterate over an array of all 26 letters. a!localVariables(
 
 local!word: "banana",
 
 local!letters: a!forEach(
 code(lower(local!word)),
 char(fv!item)
 ),
 
 local!uniqueLetters: union(local!letters, local!letters),
 
 local!counts: a!forEach(
 local!uniqueLetters,
 a!map(
 letter: fv!item,
 count: length(wherecontains(fv!item, local!letters))
 )
 ),
 
 a!forEach(
 local!counts, 
 concat(repeat(fv!item.count, fv!item.letter)) & " ----> " & fv!item.count
 )
)

Naresh · Answer

Hi, 
 Another way to achieve this logic 
 a!localVariables(
 local!word: "Banana",
 a!forEach(
 items: {
 "A","B","C","D","E","F","G","H", "I","J","K","L",
 "M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"
 },
 expression: a!localVariables(
 local!count: if(
 regexmatch(fv!item, upper(local!word), 1) > 0,
 count(regexallmatches(fv!item,local!word)),
 {}
 ),
 if(
 a!isNullOrEmpty(local!count),
 {},
 concat(repeat(local!count, fv!item), "-------", local!count)
 )
 )
 )
)

find duplicate characters count in a string

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