if() function

Certified Lead Developer

Could someone explain why the following code work without compiler errors?

    user(ri!user, "firstName") & " " & user(ri!user, "lastName"),
    joinarray(split(ri!user, "."), " ")

I expect some kind of evaluation error, but it works just as the three lines starting on "isusernametaken" were an embedded if.

I saw that in one of the Appian courses and I'm wondering if it is some undocumented feature of the if function.

Thank you

  Discussion posts and replies are publicly visible

Parents Reply Children
No Data